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evaluate 9x^2y^-2 for x=3 and y=2
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9*(3)^2*(2)^2 = ?
=324 Did that made sense to you?
the last 2 is to the -2 power not positive and yeah that made since i kinda did it like that the first time and my teacher wrote to use PEMDAS
Oh sorry did see that..
9*(3)^2*(2)^-2 = 20.25
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oh and it should say for x=-3 and y=2 my bad
9(-3)^2*(2)^2 = 324
when i did it earlier i did this 9(-3)^2 * 2^-2 = 27^2 *1/4=729* 1/4 =183.25 can you tell me where i went wrong?
First- Substitute the given x and y for the expression. Second- 9*((-3)^2)*(2^2) You first solve the parenthesis, what you did is you multiplied 9 by -3 and then you squared root it.
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