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Mathematics 16 Online
OpenStudy (anonymous):

f(x)=lx+2l; f(-4) (l's are absolute value symbols) solve for x

OpenStudy (anonymous):

it is not "solve for \(x\)" but rather "evaluate the function"

OpenStudy (anonymous):

ya

OpenStudy (anonymous):

-4=|x+2| get x by itself

OpenStudy (anonymous):

\[f(x)=|x+2|\] \[f(-4)=|-4+2|\] as a first step

OpenStudy (anonymous):

ok so its -4=-2 so would it be 2??

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