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Mathematics 22 Online
OpenStudy (anonymous):

Please CHECK my work!!! V=1/6*pih^2

OpenStudy (anonymous):

Solve for h: \[ V=1/6\pi*h^2 \] \[h=\frac{ \sqrt{6piV} }{ \pi }, h=-\frac{ \sqrt{6piV} }{ \pi }, \]

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