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(sinA+cosA)^4=1+4sinAcosA+4sin^2Acos^2
[(s+c)^2 ]^2 = [......]^2
sin^A+2sinAcosA+cos^2A
(sin^2A+2sinAcosA+cos^2A)^2
but sin^2 +cos^2 =1 this is standard!
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oh yes!!
now you'll get it
yup got it
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