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Mathematics 9 Online
OpenStudy (luigi0210):

find dy/dx

OpenStudy (luigi0210):

y=sec^2x-tan^2x

OpenStudy (luigi0210):

and also: y=sint and x=cost

hartnn (hartnn):

y=sec^2x-tan^2x use, sec^2 x = 1+ tan^2 x

hartnn (hartnn):

y=sint and x=cost square and add them, what you get ? hint : sin^2 t+ cos^2 t=1

OpenStudy (luigi0210):

Thank you!

hartnn (hartnn):

welcome ^_^

hartnn (hartnn):

ask if any doubts ...or want to verify your answer..

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