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A line passes through the points (-8, 7) and (x2, y2), and has a slope of -1/10. If point (x2, y2) is located in quadrant I, find x2.
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slope= \(\dfrac{y_2-y_1}{x_2-x_1}\)
i know that i just dont know how to find x2
ok can you show how much you have progressed?
thats how i think i can do it but i dont if im right im clueless how to do this problem y2-7 (over) x2- -8= -1/10
ok ?
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proceed
|dw:1363363929577:dw|
is x2 2
and y1 is 6
so am i right
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|dw:1363364337394:dw|
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