Hello again!

I know that: f(x)=3/x and g(x)=x-1
And need to find f(g(2))
i think I need to do like that:
$$\frac{ 3 }{ x(x-1) }=\frac{ 3 }{ x ^{2}-x }$$
and then insert 2 where is x, is it right or not?

Question

Hello again!

I know that: f(x)=3/x and g(x)=x-1
And need to find f(g(2))
i think I need to do like that:
$$\frac{ 3 }{ x(x-1) }=\frac{ 3 }{ x ^{2}-x }$$
and then insert 2 where is x, is it right or not?

mertsj · Answer

The easiest way is to replace x with 2 in the function g.  Then take that answer and replace x in the function f with it.  That will be the f(g(2))

kamille · Answer

fak, I thoughet I made a mistake. then realized I havent :/ so I get:
g(2)=2-1=1
f(g(2))=3/1=3?

mertsj · Answer

That's what I got.

kamille · Answer

thank you! I have helped me a lot recently: )

mertsj · Answer

Glad to be of service.

kamille · Answer

you* haha I think I am too tired :/