rectangular form 6(cos(150) + isin(150)) a.(3,√3,-3) B.(-3,√2,3) C.(3,√2,-3) D.(-3,√3,3)
your job is to evaluate \(\cos(150)\) and \(\sin(150)\) then multiply the result by 6
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none of the above are correct
for a variety of reasons first, standard form is not ordered pairs, it is \(a+bi\) second, \(\cos(150)=-\frac{\sqrt{3}}{2}\) and \(\sin(150)=\frac{1}{2}\)
the correct answer is \[-3\sqrt{3}+3i\]
i love your confidence @satellite73 lol
thx
still none of the answers are right, because a complex number in rectangular form is \(a+bi\) not \((a,b)\) whoever wrote this is very confused
i don't mean you, i mean the person who asked the question to begin with
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