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The anticipation is killing me
aha ikr! i feel like im at the red light waiting for it to turn green!
\[\frac{ 4x ^{3}-12x ^{2}+8x }{ -4x }\]
factor out the top
First note: $$x\neq 0$$
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I know the first part is -x^2
\[\frac{ 4x^2 }{ -4x }-\frac{ 12x^2 }{ -4x }+\frac{ 8x }{ -4x }\rightarrow -x+3x-2 \rightarrow 2x-2\]
no that's not right
So the answer is -x^2 + 3x - 2
yea
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thank you :)
np
it was 4x^3/-4x @Lynncake
ohhhhhhh \[-x^2+3x-2\]
honest mistake
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^_^
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