Question

sec B cot B =


sinB/cos²B
cosB/sin²B
1/sinB

Ive been working this out the way I have all the lessons before this, but I dont get the same answer

Answer 1

sec B cot B

sec B = (1/cos(B))

cot B = (1/tan(B))

(1/cos(B))*(1/tan(B))

tan(B) = sin(B)/cos(B)

(1/cos(B))*(1/(sin(B)/cos(B)))

(1/cos(B))*(cos(B)/sin(B))

1/sin(B)

Answer 2

Ooh, I saw those relations at the top but they didn't use the letters, they used delta and I didn't know whether I was supposed to use it. I will copy this in my notes.

Answer 3

first of all, you would have to know that,
\[\sec \theta = \frac{ 1 }{ \cos \theta } \]
\[\cot \theta = \frac{ \cos \theta }{ \sin \theta }\]

Answer 4

you would have to substitute that in your question and solve it.

Answer 5

Thank you both, I think I have it now, if I run into any problems Ill def. message you both.