Question

about absolute maxima and minima..>O<

Answer 1

Did you find the critical points?

Answer 2

NO...?

Answer 3

do i have to use second derivative?

Answer 4

You use the first derivative to find critical points.

Answer 5

You can use the second derivative, but don't need to.

Answer 6

okkayyy mmm...so when should i use the second derivative?

Answer 7

Well, come back with the first and second derivative and I'll tell you.

Answer 8

okayy ill @ u when im finished:)

Answer 9

derivation of c(t) is 60t-240

Answer 10

@wio

Answer 11

then what should i do?:)

Answer 12

Wow, did you use the definition of the derivative?

Answer 13

????

Answer 14

Okay now solve for \(t\): \[
60t-240 =0
\]to get critical points.

Answer 15

It just took you a while to get the derivative....

Answer 16

lol yeah i just start this lesson and kind of slow:D

Answer 17

4

Answer 18

Okay, now plug in \(4, 0,\) and \(8\) into \(C(t)\) to find the values.

Answer 19

The maximum/minimum values will be at the critical points and end points.

Answer 20

I dont get it why 8?

Answer 21

because \(0\leq t\leq 8\)

Answer 22

So 0 and 8 are endpoints and must be checked.

Answer 23

yeahhhh right ~what should i do after it?

Answer 24

What is \(C(0), C(4), C(8)\) ?

The smallest is the minimum, the highest is the maximum. It shouldn't be hard to compare 3 numbers.

Answer 25

i see

Answer 26

i need some time ill @ u lol

Answer 27

@wio c(0)=500 c(4)=20 c(8)=500..

Answer 28

thats weird=_=

Answer 29

mmm..we can get the first ques now right???

Answer 30

after 4 days????(⊙⊙?)

Answer 31

Yeah

Answer 32

what the minimum concentration?what does that mean?=A=

Answer 33

IM SOOO sorry @wio

Answer 34

@wio ^ω^

Answer 35

ummm

Answer 36

So after 4 days the minimum concentration is 20...

Answer 37

↖(^ω^)↗i seeeee thanks soooooooo much

Answer 38

im sorrry i dont get english much lol

Answer 39

What is your language?

Answer 40

persian and my mother speaks english but i grew up in china=A= KInd of complicated lol