Question

At 9:00 on Saturday morning, two bicyclists heading in opposite directions pass each other on a bicycle path.The bicyclist heading north is riding 4 km/hour faster than the bicyclist heading south. At 10:30, they are 39 km apart. Find the two bicyclists’ rates.
(A)northbound bicyclist = 15 km/h; southbound bicyclist = 11 km/h
(B)northbound bicyclist = 17 km/h; southbound bicyclist = 11 km/h
(C)northbound bicyclist = 15 km/h; southbound bicyclist = 10 km/h
(D)northbound bicyclist = 16 km/h; southbound bicyclist = 12 km/h

Answer 1

D.) Let me explain...

Answer 2

when i tried the problem i got C

Answer 3

So 1.5hours*(2x+8 km/hour)=48 km
2x+8=48/1.5
2x+8=32
2x=24
x=12
This is wat I got...

Answer 4

Is tht rite @Mertsj ?

Answer 5

I was going to answer, but @e.cociuba with here you are in good hands

Answer 6

Hahah thanks @Luis_Rivera

Answer 7

Should be 2r + 4

Answer 8

thank u soo much

Answer 9

So I did It wrong...