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Graph has a vertex at (−1,−2) and passes the point (0,−1). Find the quadratic function.
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\[y=a(x-h)^2+k\]
Plug in and solve for a. h = -1, k = -2, x = 0, y = -1
hmm i got -3(x+1)^2 + 3
a(x+1)^2 + 4 a(0+1)^2+4 a(1)+4 -1=1a+4 -5==1a a=-5
-5(x+1)^2 + 4??
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-1=a(0+1)^2-1 -1=a(1)-1 a=|dw:1363403122732:dw|
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