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Ok last one.....
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Let \[\int\limits_{-3}^{6}f(x)dx=8\] \[\int\limits_{-3}^{0}f(x)dx=8\] \[\int\limits_{3}^{6}f(x)dx=1\] Find \[\int\limits_{0}^{3}f(x)dx\] and \[\int\limits_{3}^{0}\left( 8f(x)-8 \right)dx\]
1.->8+a+1=8->a=-1 2.8(-(-1))-8(0-3)=8+24=32
must have just messed up the math when I tried the first one
cool thanks! Now I'm going to head to algebra to see if I can help anyone there to make up for it. :)
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