Question

what is the simplified trig expression for csc theta sin theta-sin^2 theta?

Answer 1

we knowed that csc(theta) = 1/sin(theta)
so, csc theta sin theta-sin^2 theta = 1/sin(theta) * sin(theta) -sin^2 theta
= 1 - sin^2 theta

Answer 2

then use the identity sin^2(theta) + cos^2(theta) = 1
we get 1 - sin^2 theta = cos^2(theta)

Answer 3

I have that so far but wasn't sure what to do with 1-sin^2theta

Answer 4

first of all you would have to know that
\[\csc \theta = \frac{ 1 }{ \sin \theta } \]