Question

Given that sin(A+B)=4/5 and cos(A-B)=12/13 with the condition that 0 13 years ago

Answer 1

Okay ..



=> tan(A+B) = 4/3
And tan(A-B) = 5/12

tan{(A+B)+(A-B)} = tan(A+A) = tan(2A)

tan{(A+B)+(A-B)}
\[\frac{\tan(A+B) + \tan(A-B)}{1- \tan(A+B) \tan(A-B)}\]

Substitute the values and you'd get the answer :D