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OpenStudy (anonymous):
sin^7(x)cos^5(x)dx ?
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OpenStudy (anonymous):
Take integral, right? if so, Let u =sin x --->du= cos x dx. and you have cos^5 = (cos^2)^2. cosx . and then, 1-sin^2 = cos^2 ---> (1-u^2)^2 is last part . replace everything into yours and take integral
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