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Mathematics 13 Online
OpenStudy (anonymous):

integral from 1 to 4 sqrt of 4t^2-4t+16t^6dt

OpenStudy (anonymous):

everything comes in sqr root?

OpenStudy (ryan123345):

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OpenStudy (anonymous):

I think it is f(4) - f(1) but I am not very sure.

OpenStudy (anonymous):

make that square root in bracket ( ) ^ 1/2 then solve

OpenStudy (anonymous):

but cant you find the value and take its square root?

OpenStudy (anonymous):

uh,no lol

OpenStudy (anonymous):

Is this the integral? \[\int_1^4\sqrt{4t^2-4t+16t^6}\;dt\]

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