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integral from 1 to 4 sqrt of 4t^2-4t+16t^6dt
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everything comes in sqr root?
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I think it is f(4) - f(1) but I am not very sure.
make that square root in bracket ( ) ^ 1/2 then solve
but cant you find the value and take its square root?
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uh,no lol
Is this the integral? \[\int_1^4\sqrt{4t^2-4t+16t^6}\;dt\]
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