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3sec^2x-6=8tanx. Solve for x
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\[3\sec ^2x-6=8\tan \tan x\]
Is that it?
(With only 1 tan of course)
yepp..thats the question! i wasnt too sure on how to use the circumflex looking like thing!
Get it equal to 0 and factor it.
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\[3(1+\tan ^2x)-6=8\tan x\]
\[3\tan ^2x-8\tan x-3=0\]
\[(3\tan x+1)(\tan x-3)=0\]
Take it from there.
thanks!
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yw
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