Question

precalculus

Answer 1

its a really hard one its eating my brain

Answer 2

@Ayeshaafzal
it seems more of quadratic and trigonometry to me.....

anyways with calculus you can proceed this way
1. in the vertical direction acc = g (downward) so you can write the equation for it`s y coordinate
2. similarly do this for horizontal direction (there is no acc in this direction)

Answer 3

yes i know that and then u solve equation utcosa =utsina-1/2gt^2 but i dont know how

Answer 4

y = usin(theta) - 1/2 gt^2
x = ucos(theta) *t

then put the value of x = h and y = h to get the values of T1.
can you find T1 now?