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PLEASE EXPLAIN: In this equation the variable z has two possible value is -2. What is the other possible value of z? -4|4z+2|=-24
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You can solve this problem by setting 4z+2 = -6 and 4z+2 = 6
yes, technically, to get rid of a "modulus", you have to square it
\[ x^2=y\\ \implies |x|=\sqrt{y} \]
@wikiemol what would be the next step. To subtract two from both sides?
so the other answer to z would be 1? correct? @wikiemol
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for the first equation: 4z=-6-2 4z=-8 z=-2 for the second equation 4z=6-2 4z=4 z=1
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