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Write the terms of the series and find their sum ∑k=14(k+2)2
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wait wrong equation
@samtasticc
\[\sum_{k=1}^{4} (k+2)\]
\[(k+2)^{2}\]
\[\sum_{k=1}^4(k+2)^2\]??
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put \(k=1\) get \((1+2)^2=3^2=9\) put \(k=2\) get \((2+2)^2=4^2=16\) etc then add up the four numbers
Yes thats correct
i.e. add up \(9+16+25+36\)
so you keep going like k=3 and k=4 and then those four numbers added together is the answer?
What are the terms of the series? 9,16,25 & 36 @satellite73
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