Question

Find the focus of the parabola x = –2(y – 3)^2 - 2.

Answer 1

re write the equation

x + 2 =-2(y-3)^2

now divide both sides by -2

\[\frac{-1}{2} (x +2) = (y -3)^2\]

the general from is

4a(x -h) = (y -k)^2

(h, k) is the vertex and a is the focal length...

the focus will be (h - a, k)

the parabola is concave left...