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OpenStudy (anonymous):
identify the vertex, focus and directrix of the graph equation. x=1/24y^2
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OpenStudy (amistre64):
you need to be able to recall the geometric equation of a parabola
OpenStudy (amistre64):
4ay = x^2 to adapt it to your situation, 4ax = y^2 would seem to fit
OpenStudy (amistre64):
x = 1/24 y^2 24x = y^2 4a = 24, what is a?
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