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OpenStudy (anonymous):
Please Help Write term of serious and sum.... equation on bottom.
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OpenStudy (anonymous):
\[\sum_{k=1}^{4} (k+3)^{2}\]
OpenStudy (anonymous):
Can you foil it out?
OpenStudy (anonymous):
Fot the sum i got 58 is that right? @wio
OpenStudy (anonymous):
\[ \sum_{k=1}^{4} (k+3)^{2} = (1+3)^2+ (2+3)^2+ (3+3)^2+ (4+3)^2 \]
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