Suppose that a population of measurements is normally distributed with mean μ and standard deviation σ. (Round your z value to 2 decimal places and the remaining answers to 3 decimal places.)

Write an expression (involving μ and σ) for a tolerance interval containing 98 percent of all the population measurements.

Question

Suppose that a population of measurements is normally distributed with mean μ and standard deviation σ. (Round your z value to 2 decimal places and the remaining answers to 3 decimal places.)

Write an expression (involving μ and σ) for a tolerance interval containing 98 percent of all the population measurements.

ryan123345 · Answer

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anonymous · Answer

$$
Z = \frac{X-\mu}{\sigma }
$$

anonymous · Answer

In this case we have $X= 98\% = 0.98$