Question

For a rectangle with a perimeter 32 to have the largest area, what dimensions should it have?

Answer 1

you're give 2L + W = 32 where L is length and W is width

Answer 2

Area = LW = L x (32 - 2L)

Answer 3

Now maximize Area

Answer 4

do I take the derivative

Answer 5

Yes. Find V' of L x (32 - 2L).

Answer 6

how do I find the derivative? I keep getting the wrong answer