Question

How is this factored::::: 125x^3-27=0
using the sum or difference of cubes to find the real or imaginary solutions

Answer 1

difference of two cubes.

Answer 2

(5x)^3-(3)^3

Answer 3

but what about the part where you plug it into the formula my real question is does the -3 stay negativ when plug-in her into the formula where the -b is

Answer 4

the general form is

\[a^3 - b^3 = (a -b)(a^2 + ab + b^2)\]

in your question a = 5x and b = 3

Answer 5

thanks :) i wrote the formula wrong

Answer 6

glad to help