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calcII y=x^2, x=1, y=0 around x=2 using the shell method. ans 5pi/6 drawing below.
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|dw:1363580063342:dw|
What's your plan? \(2\pi\int\limits_{??}^{??} Radius\cdot Height\;dx\)
pretty much
Okay, fill in the blanks.
i've figured out most of the pieces.
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What are the limits of the integration?
2π∫(0,1)1⋅x^2dx
Not quite. Radius is (2-x)
should it be in terms of y? that's what my book says.
Limits are also [1,2]. dy for shells? No.
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no, your misunderstanding the question.
Yup. I wraped the wrong piece. It's still not dy.
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