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Mathematics 6 Online
OpenStudy (anonymous):

5x^2-32x+12=

OpenStudy (anonymous):

is -10 a answer?

OpenStudy (anonymous):

\[5x^2-32x+12=\]

OpenStudy (anonymous):

have you tried factoring it?

OpenStudy (anonymous):

nope,,..

OpenStudy (anonymous):

ohh i means yess

OpenStudy (lasttccasey):

You need this to equal something in order to solve for x or you need an x to see what it equals.

OpenStudy (lasttccasey):

Is this factoring?

OpenStudy (anonymous):

solve for x

OpenStudy (anonymous):

its like factoring diamod

OpenStudy (lasttccasey):

(x-6)(5x-2)=? you can't solve x without it equaling zero or something.

OpenStudy (anonymous):

okey thankx :)

OpenStudy (anonymous):

\[6x^2+5x-4=\]

OpenStudy (lasttccasey):

=(2x-1)(3x+4) Do you understand how to factor these?

OpenStudy (anonymous):

5x^2-30x-2x=12 5X(X-6) -2(X-6) (5X-2) (X-6) X=2/5 and x=6

OpenStudy (anonymous):

no.. u, u\

OpenStudy (anonymous):

*5x^2-30x-2x+12 not equals 12 on the first row

OpenStudy (lasttccasey):

@bangabus000 Thats technically incorrect, you can't bring over the 12 without knowing whats on the right side.

OpenStudy (anonymous):

umm yeah... no i made an error while typing its plus 12 not equal

OpenStudy (lasttccasey):

I'm just saying, you can't solve for x if the right side is missing. it could be 0 but it could also be 100 or anything for that matter.

OpenStudy (anonymous):

ofcourse its 0 on the other side. i thought that was obvious since we were factoring.

OpenStudy (anonymous):

the x values are correct right?

OpenStudy (lasttccasey):

@chubbytots But using bangabus000's method, factoring by parts, is the best way to solve this type. @bangabus000 If it equals zero yes :)

OpenStudy (anonymous):

hehehe :p

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