Question

the positionfunction of a moving particle is s(t)= ((t^3)/6)-((t^2/2))+t-3 for 0 less than or equal to t less than or equal to 4. what is the maximum velocity of the particle on the interval 0 less than or equal to t less than or equal to 4?

Answer 1

\[s(t)=\frac{ t ^{3} }{ 6}-\frac{ t ^{2} }{ 2 }+t-3\]