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Mathematics 7 Online
OpenStudy (anonymous):

if sinx = 1, find x and if sinx = -1/2 , find x

OpenStudy (anonymous):

\[x= \sin^{-1} (1)\] \[x=\pi/2\]

OpenStudy (anonymous):

x=pi/2+2npi

OpenStudy (anonymous):

actually the question is , find general solution

OpenStudy (anonymous):

ya we add 2npi in case of general solution (period of sin is 2pi)

OpenStudy (anonymous):

n denotes any integer

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