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(a) Solve the following simultaneous equations. x-2y=20 x^(2)+3y=15 >>>Why there have two answers for both x and y? (b) Hence solve the following simultaneous equation. xy-2x-2y=20 x^(2)y^(2)+3x+3y=15 >>>>I cannot get the answer...
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|dw:1363611645831:dw| so insert 20+2y into second eq, where is x, and you will find y
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