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I have the answer can someone please check me... Find the derivative p(x)=10x^2sin(10x)
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this isi the equation for the question\[p(x)=10x^2\sin(10x)\]
product plus chain rule
\((fg)]=f'g+g'f\) with \(f(x)=x^2,f'(x)=2x,g(x)=\sin(10x),g'(x)=10\cos(x)\)
damn i meant \(g'(x)=10\sin(10x)\)
and factor that first ten out of the whole thing
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I got 20xsin(10x)+100x^2cos(10x)
looks good to me
ok thanks
if you want to be fancy you can factor \(20x\) out of both terms
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