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what is the solution of n^2-49=0
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squareroot of n^2 =49
square root of 49 is 7
no not the squareroot of 49 the square root of a number squared (n^2) equals 49
i still dont get it
the solution is n=49
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because you are solving you would add 49 to both sides because you are trying to get n alone and you would get n^2=49 and then you would need to find the squareroot of n to get n alone so you would get n=49
wrote the equation wrong. its ... n^2 -49=0
is it -7, 7, \[\pm7\], or no solution?
i didn't mention the equation acutally
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