9. Write an equation of a circle with the given center and radius.

center (–7, –6) and radius 2 (1 point)(x + 7)2 + (y + 6)2 = 4
(x – 7)2 + (y – 6)2 = 2
(x + 7)2 + (y + 6)2 = 2
(x – 7)2 + (y – 6)2 = 4

Question

9.   Write an equation of a circle with the given center and radius. 

center (–7, –6) and radius 2   (1 point)(x + 7)2 + (y + 6)2 = 4
(x – 7)2 + (y – 6)2 = 2
(x + 7)2 + (y + 6)2 = 2
(x – 7)2 + (y – 6)2 = 4

campbell_st · Answer

the general form is 

$$(x - h)^2 + (y - k)^2 = r^2$$

where (h, k) is the centre and r is the radius 

in your question centre(-7,-6) so h = -7 and k = -6 and r = 2. Substitute them for the answer.

anonymous · Answer

(x-h)^2+(y-k)^2=r^2
(x--7)^2+(y-6)^2=2^2
(x+7)^2+(y+6)^2=4      <---- is this my answer????

campbell_st · Answer

and that would be correct