Question

Part 1: Solve each of the quadratic equations below. Show your work. (3 points)

x2 - 36 = 0 and x2 = 8x - 12

Answer 1

can someone please explain how to do this?

Answer 2

the 1st one is the difference of 2 squares

since there are only 2 terms... what are both squares

then factored form is

(x -6)(x+6) = 0

the 2nd question need to be rewritten as

\[x^2 -8x + 12 = 0\]

this can be factored.... you need to find the factors of 12 that add to -8, both factors are negative

then the factored form of the equation is

(x + factor 1)(x + factor 2) = 0

does this make sense..