Question

Rewrite the equation in vertex form. Name the vertex and y-intercept.
y = x^2 – 10x + 15
y = (x – 10)^2 –10
vertex: (–10, –10)
y-intercept: (0, –10)
y = (x – 5)^2 – 10
vertex: (5, –10)
y-intercept: (0, 15)

y = (x – 5)^2 + 40
vertex: (5, –10)
y-intercept: (0, 15)
y = (x – 10)^2 + 20
vertex: (–10, –10)
y-intercept: (0, –10)

Answer 1

I think the answer is y = (x – 5)^2 – 10
vertex: (5, –10)
y-intercept: (0, 15)
just btw

Answer 2

http://www.algebra.com/algebra/college/linear/Linear_Algebra.faq.question.117607.html

Answer 3

follow the process

Answer 4

Alright thank you :)

Answer 5

you are welcome x)