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What is the simplified form of the quantity x squared minus 9 over the quantity x minus 3 ?
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\[\frac{ x^2-9 }{ x-3 }\] ?
is that correct?
well im asking if that is the question, typed out correctly because if so this is a simple factoring problem. Take the x^2-9 and factor that out into (x+3)(x-3) so this becomes \[\frac{ (x+3)(x-3) }{ (x-3) }\]
the x-3's cancel out and you are left with just the (x+3) as your answer
@DeadShot did this help?
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