Question

Rewrite the equation in vertex form. Name the vertex and y-intercept. y = 3/5x^2 + 30x + 382
A)y = (3/5x + 25)^2 + 7
vertex: (—25, 7)
y-intercept: (0, 382)
B)y = (x + 30)^2 + 518
vertex: (30, 518)
y-intercept: (0, 7)
C)y = ( 3x/5 + 25)^2 + 7
vertex: (25, —7)
y-intercept: (0, 7)
D)y= ( 3/5x + 5)^2 +21/5
vertex: (—5,21/5 )
y-intercept: (0, 382)

Answer 1

for y intercept put x=0 in the equation

Answer 2

So the answer is either D or A because both of those y intercepts are (0,382)