Question

Use the quadratic formula to solve the equation below.

-6x= -4x^2 +18

A. X=3 | X= -1.5
B.X=1.5 | X= -3
C.X=3 | X= -3
D.X=-3 | X= -1.5

Answer 1

Do you think you might be able to help? @ash2326

Answer 2

Standard form of a quadratic equation
\[ax^2+bx+c=0\]
here we have
\[-6x=-4x^2+18\]
or
\[4x^2-6x-18=0\]
Do you get this part? I've just rearranged the equation :)

Answer 3

Yes.

Answer 4

The solution of quadratic equation is
\[x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\]
here
a=4
b=-6
and c=-18
Can you plug in the values and solve for x?

Answer 5

Can you help me on how to find x. I don't quite get it.

Answer 6

ok :)

Answer 7

\[x=\frac{-(-6)\pm \sqrt{(-6)^2-4\times 4 \times (-18)}}{2\times 4}\]
\[x=\frac{
-(-6)\pm \sqrt{36+288}}{2\times 4}\]

\[x=\frac{
-(-6)\pm \sqrt{324}}{2\times 4}\]
\[x=\frac{
6\pm \sqrt{324}}{2\times 4}\]
\[x=\frac{6\pm 18}{8}\]
so
\[x=\frac{6+18}{8}, \frac{6-18}{8}
\]
Just simplify now :)

Answer 8

So i just did 6+18=24 and then divided it by 8 and got 3

Answer 9

yes, find the other one also

Answer 10

Then I did 6-18= -12 and -12 divided by 8 and got -1.5

Answer 11

So it would be A

Answer 12

correct :) Did you understand?

Answer 13

Yeah. Better then I did before

Answer 14

Thank you :) I have a few more if you wouldn't mind helping me

Answer 15

I'm here for some time, I can help :P|)