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Evaulate the following: log (base 9) (1/9) .
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So that's all I put for the final answer? @paddyfitz
yeahh, maybe a little bit more working, sorry I should have been a bit clearer. basically\[\log_{10}100 = 2\] so the logarithm is like 'what power do i need to raise the base to, in order to get the number INSIDE the log'. Bit of a confusing concept. So like, what power would you have to raise 9 to, in order to 1/9? It would be -1, as 9^(-1)=1/9 :)
Thank you so much! :) @paddyfitz
Can you help with the latest question? @paddyfitz
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