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Determine the number of real solutions of -2x^2 + 5x - 3 = 0. A. 0 B. 1 (double root) C. 2
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@jim_thompson5910
what did you get
you can either factor or you can use the quadratic formula
I got B
oh wait, they don't want the solutions themselves
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they want the number of solutions
so you use D = b^2 - 4ac
yep and i got B, wouldnt that be right?
tell me what you get when you evaluate D = b^2 - 4ac
plug in a = -2, b = 5, c = -3
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2
D = b^2 - 4ac D = 5^2 - 4(-2)(-3) D = 1 So you were close
since this discriminant is greater than 0, you get 2 real solutions
so that's why the answer is C
ohhh gotchya!
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