Question

e^x=2 how do you solve for x?

Answer 1

write it in logarithmic form....
\(\large b^x=y \leftrightarrow x=log_by \)

Answer 2

in this case use natural log

Answer 3

Apply natural logarithm in both sides of the equation
\[\ln(e^x)=\ln2\]
By the logarithm properties,
\[xln(e)=\ln2\]
and lne=1, so finally
x=ln2