Question

log__1/16=-2
I'm trying to find the base

Answer 1

suppose base is b
b^-2 = 1/16

Answer 2

So basically you are trying to solve this equation:
\[x ^{-2}=\frac{1}{16}\]

Answer 3

b^-2 = 4^-2
therefore b = 4

Answer 4

Oh okay I how you all solved this.. Thank you so much

Answer 5

Okay how will you go about log_6=-1/3