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Construct a cubic polynomial with real coefficients, one of whose zeros is 6 + i, and passing through the point (-1,20).
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If it is a polynomial with real coefficients, that means your complex root has a partner, it's conjugate, which is 6-i. This will create a quadratic.
Now as @calmat01 has said, U now know two roots form a cubic polynomial\[ax ^{3}+b ^{2}+cx+d=0\] and find the other root
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