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In how many ways can 2 different ice cream toppings be chosen from 12 available toppings?
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@anlnt4 Do you know combinations?
we're learning them now, I think. I know the answer, I just don't know how to get it.
What is the answer?
66
12 choices for the first topping, then 11 for the second topping so \(12\times 11\) exept that the the order you choose does not matter, so divide that by 2
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in other words it is \(\frac{12\times 11}{2}=6\times 11=66\)
So anytime the order doesn't matter you'd divide it by the number you need?
Thanks!
yw
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