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The directions say to solve each equation by first clearing the fractions or decimals 0.2(c-4)+1=0.15(c+2) i am supposed to get positive 2 but this is what i got. .2c-.8+1=.15c+.30 .2c=.15c-1.8+.30 .2c=.15c-1.5 .05c = -1.5 C=-30 please help and tell me what i did wrong. thank you
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here it is, step by step http://openstudy.com/study#/updates/51493935e4b05e69bfab9f5a
rewrite it as \[ {20\over100}(c-4)+1={15\over100}(c+2) \]
you must have the same on line class, it is the same question i just answered exactly
except the last line should read \(c=10\div5=2\)
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