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sinx+cosecx=2 sin^8x+cosec^8x=?
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A better method than binomial expansion? :/
i got it :)
sinx + 1/sinx = 2 sin^2 x +1 = 2sinx sin^2x - 2sinx + 1 = 0 Use Quadratic Formula to find the value of sinx
no use of quadratic formula..it is simply (sinx-1)^2=0 sinx=1 ....)
Any how
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