The topmost and bottom most velocities of a disc are v1 and v2 in the same direction.The radius is R.Find out the velocity of the point which is R/2 above the centre?
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OpenStudy (dls):
@RnR
OpenStudy (anonymous):
Pta nhi. :/
@Mashy
OpenStudy (dls):
don't be so dependent :/
OpenStudy (dls):
IIT exam mein :P
@Mashy
OpenStudy (anonymous):
Rotate kr rhi hai disc?
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OpenStudy (dls):
but dependency ki baat kaun kar raha h :P hmm
OpenStudy (dls):
pata nahi :/
OpenStudy (anonymous):
hmm. ho skta hai.. wait.
OpenStudy (dls):
:/
OpenStudy (dls):
|dw:1363807863482:dw|
oho diagram :P
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OpenStudy (anonymous):
5v1-3v2/2 ?
OpenStudy (dls):
nowhere near
OpenStudy (anonymous):
3v1-v2/4 ? calculation mistake.
OpenStudy (dls):
kaise kiya?
OpenStudy (anonymous):
v1-v+wr
v2=v+wr
where v is vel of centre of mass
two equations. solve for v and w
vel at a point r/2
v+wr/2.
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OpenStudy (dls):
though the answer is 3v1"+"v2/4 ?
OpenStudy (anonymous):
ohho. haan another calc mistake. aa rha hai.
OpenStudy (dls):
v1=v+wr kahan se aati hai vise?o.O
OpenStudy (anonymous):
correction: v2=v-wr
aur topmost point pe vel maximum hoti hai na.. isliye.
OpenStudy (dls):
oh :O got it :D!
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OpenStudy (anonymous):
:D
OpenStudy (vincent-lyon.fr):
|dw:1363852614084:dw|
If V1 and V2 are parallel, then the instant centre of rotation is on the dashed diameter of the disc, perpendicular to V1 and V2.
Velocities of points along this diameter follow a simple linear law as shown.